How do I get each value of an array and put it in separate variables.

[ajnoguerra]

Hi guys, can anyone please help me out:
How do I get each value of an array and put it in separate variables.

here’s the array:

Array ( [0] => 1946 [1] => 6 [2] => 10 )

This is a birthday in an array, I’d like to get each value and put it in 3 variables which is the $Year, $Month, $Day. So I can output it as “Month Day, Year”.

Please please help. Thanks.

[CrocoDillon]

Your array declaration is invalid. If you make it like:

array(1946, 6, 10);

or

array(0 => 1946, 1 => 6, 2 => 10);

if you must, you can then use

$year = $whatever_array[0];

[ajnoguerra]

Actually got an answer for this problem. :D

$selectbirthday = array ( [0] => 1946 [1] => 6 [2] => 10 );

$resultyear = $selectbirthday[0];

echo $resultyear;

output is: 1946

[CrocoDillon]

Really? What PHP version do you use because I definitely getting an error on that array syntax (PHP Version 5.3.13)

[ajnoguerra]

@CrocoDillon, what you posted recently was correct. I actually forgot to mention that I fetched the values of the array from a database field and used “explode()” function to reference them individually. This is actually the output when I print_r “_array ( [0] => 1946 [1] => 6 [2] => 10 );_”

But this is the correct way:

$selectbirthday = array( 0 => 1946, 1 => 6, 2 => 10 );

$resultyear = $selectbirthday[0];

echo $resultyear;

Thanks for the help! (thumbs up)

[CrocoDillon]

You sure know how to puzzle my mind! I’m glad it’s solved :)

[__]

you could also do like so:

$ymd = array( 1946,6,10 );
list( $year,$month,$day ) = $ymd;
print “Year: $year”;

[`list()`](http://php.net/list) is underappreciated… : )

[Author]

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