Re: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result error

[LaurelBrittany]

I ran the code as you described as being correct in your first comment and got this:

“This code has failed “

<form method="post" action="<?php $_SERVER;?>">

<?PHP

// Get the ID and Table name into variables

$id = $_GET;

$table = $_GET;

$title = $_GET;



include('includes/dbc_admin.php');

$sql = "SELECT * FROM $table where id = '$id'";

$result = mysql_query($sql);

if($result) {

while($row=mysql_fetch_assoc($result))

{

echo '<div>ID</div><input style="hidden" name="id" value="'.$id.'"><br/><br/>';

echo '<div>Table</div><input style="hidden" name="table" value="'.$table.'"><br/><br/>';

echo '<div>Title</div><textarea name="title" width="500">'.$row.'</textarea><br/><br/>';

echo '<div>Message</div><textarea name="message" width="500" height="300">'.$row.'</textarea>';

}

}

else {

echo 'This code has failed';

}

?>

<input type="submit" name="Submit_Update" value="Update">

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