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February 24, 2015 at 9:14 pm
#196722
Shikkediel
Participant
No problem, @justdan. Here’s an even niftier version where you can specify a whole sequence of left
positions (in this case they are set directly and are not added upon the previous position – so make sure the last one is zero) and the function will then automatically loop through all. With a random timing in between 300 and 700 ms per step :
:-)