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#196722
Shikkediel
Participant

No problem, @justdan. Here’s an even niftier version where you can specify a whole sequence of left positions (in this case they are set directly and are not added upon the previous position – so make sure the last one is zero) and the function will then automatically loop through all. With a random timing in between 300 and 700 ms per step :

http://jsfiddle.net/RHCqQ/46/

:-)