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Shuffle DOM Elements

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This is from James Padolsey. Check out his article for a pure JavaScript technique as well.


    $.fn.shuffle = function() {
        var allElems = this.get(),
            getRandom = function(max) {
                return Math.floor(Math.random() * max);
            shuffled = $.map(allElems, function(){
                var random = getRandom(allElems.length),
                    randEl = $(allElems[random]).clone(true)[0];
                allElems.splice(random, 1);
                return randEl;
        return $(shuffled);


Target elements, call shuffle.

$('ul#list li').shuffle();


  1. Vladimir Komarov
    Permalink to comment#

    Thank you for this post – it’s useful. I’m going to read again jQuery docs about map, get and replaceWith, and about native js splice as well.

  2. Alexandre Cárdenas
    Permalink to comment#

    Your web design is awesome. I love it. Congratulations!


  3. Kiran
    Permalink to comment#

    Great piece. Thank You.

  4. Nitin
    Permalink to comment#

    Great plugin. Thanks a million.

  5. Trevor
    Permalink to comment#

    Anyone have an idea how to make this work if you want to randomize say two different lists on the same page? Yes I could assign a different ID to each list then suffle them like so:

    $(‘ul#list1 li’).shuffle();
    $(‘ul#list2 li’).shuffle();

    But what I’d like to be able to do is just go:
    $(‘ul.randlist li’).shuffle();

    And that would then randomize just the list items within that UL, even if I had multiple lists on a page. Right now what it does it randomizes all the list items across ALL the ul’s with that class. Which is not what I want as the list items need to stay with their parent.

  6. Jesse

    Trevor, this is simple using each()


  7. Jesse

    Also, I noticed that this plugin will break references to the original elements (since it actually copies them). I wrote a version that actually shuffles the original elements.


    $.fn.shuffle = function() {
      var elements = this.get()
      var copy = [].concat(elements)
      var shuffled = []
      var placeholders = []
      // Shuffle the element array
      while (copy.length) {
        var rand = Math.floor(Math.random() * copy.length)
        var element = copy.splice(rand,1)[0]
      // replace all elements with a plcaceholder
      for (var i = 0; i < elements.length; i++) {
        var placeholder = document.createTextNode('')
        findAndReplace(elements[i], placeholder)
      // replace the placeholders with the shuffled elements
      for (var i = 0; i < elements.length; i++) {
        findAndReplace(placeholders[i], shuffled[i])
      return $(shuffled)
    function findAndReplace(find, replace) {
      find.parentNode.replaceChild(replace, find)


  8. Andrew Van Wart

    Excellent tip! I would just add that if you have nested list items (ul ul li) within your parent ul#list, in order to only randomize the parent list items, use this code to initialize:

    $('ul#list > li').shuffle();
  9. Trevor

    Thanks Jesse! Wow, that was an easy fix, I clearly need to learn jQuery better. And good stuff with your updated shuffle function!

    I just wondered what exactly you meant by the function “will break references to the original elements”?

  10. Markus
    Permalink to comment#


  11. Rahul
    Permalink to comment#

    What is the minimum number of item required?

  12. Shahab

    Nice solution :)
    I’ve made a small change to make a plugin to randomly remove some items:
    (function($) {
    $.fn.randomRemove = function(n) {
    var allElems = this.get(),
    getRandom = function(max) {
    return Math.floor(Math.random() * max);
    if (allElems.length > n) {
    while (n > 0) {
    var random = getRandom(allElems.length);
    allElems.splice(random, 1);
    return $(allElems);

  13. Aamir Afridi
    Permalink to comment#

    Or just try this

    var parent = $("#shuffle");
    var divs = parent.children();
    while (divs.length) {
            parent.append(divs.splice(Math.floor(Math.random() * divs.length), 1)[0]);
  14. binaryum
    Permalink to comment#

    Nice one @jess. Really helped, the other options were breaking the references, therefore, breaking my app!
    Thanks again!

  15. Donnie Kerr
    Permalink to comment#

    Thank you! Helped me out big time!

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