NodeJs – How to bundle tests and start karma from watch task

[matthisco]

Whenever the appropriate files change I would like to bundle my tests and start karma, showing any failed tests.

I currently have the watch task:

gulp.task('default', ['browserify', 'css','runTests'], function () {
    gulp.watch('./src/js/**/*.js', ['browserify']);
    gulp.watch('./src/js/**/*.js', ['runTests']);
});

Which starts up the runTests.js

gulp.task('runTests', function() {

    var testFile = [
        './src/components/tests/suite.js'
    ];

    // bundle tests
    var cmd = child_process.spawn('browserify', ['-e', 'D:\\Source\\lookedaftercall\\react\\src\\components\\tests\\suite.js', '-t', 'reactify', '-t']);

    cmd.on('close', function (code) {
        //cmd finished start karma
        gulp.src(testFiles)
            .pipe(karma({
                configFile: 'karma.conf.js',
                action: 'run'
            }))
            .on('error', function(err) {
                throw err;
            });
    });

my console currently errors here:

[17:04:27] Starting 'runTests'...
[17:04:27] Finished 'runTests' after 2.73 ms
events.js:85
  throw er; // Unhandled 'error' event
        ^
Error: spawn browserify ENOENT
at exports._errnoException (util.js:746:11)
at Process.ChildProcess._handle.onexit (child_process.js:1053:32)
at child_process.js:1144:20
at process._tickCallback (node.js:355:11)
at Function.Module.runMain (module.js:503:11)
at startup (node.js:129:16)
at node.js:814:3

Process finished with exit code 1

Can anyone please help? IS there a better way I can automate this process?

[Author]

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