how to make variable for html code

[ahmed18]

Hey guys

I make this

echo $val ;



?>

$val will display HTML code by user like this code

but image not appear and display this

http://localhost/wp/%5C%22http://localhost/val.jpg%5C%22

[bungle]

I would guess that the user HTML code is not being escaped and unescaped correctly when it is being stored. Are you storing it in a database and if so are you handing the strings correctly with addslashes() or mysql_real_escape_string() before storing and then unescaping them afterwards before echoing them out? Or are you sending them as a get variable and then not using urldecode()?

It looks like a combination of both has happened – i.e. that result looks like it has first been escaped and then url encoded

[ahmed18]

No I don’t use database , I am getting HTML code from textarea content will user put

[bungle]

so the user is posting it with a form? what’s the rest of your code?

[ahmed18]

I want only make variable display HTML code correctly

[bungle]

sorry but you are not providing enough information to tell you why that is happening.

PHP is a pre processing language, your user input must be getting to the php somehow, either by being passed as a GET or POST variable, or by being recalled from a database.

How is the $var variable being set? and how is it being read to generate your unwanted output?

Need to see all the code to figure that out, what you have provided isn’t enough.

[ahmed18]

it is not script , it is options page for wp theme

and i make textarea for putting analytical code and then i use echo to print it in footer

[ahmed18]

It is the same problem I face
http://www.wptavern.com/forum/plugins-hacks/1859-theme-options-page-problem-html-text-textarea-inputs.html

but when I use code for solution give me error

echo stripslashes(get_settings('content')

[ahmed18]

thx alot
I have been used htmlentities() and htmlspecialchare()
but both of them display HTML code like text not give it’s function for displaying image

[ahmed18]

thx but still not working

[Zeriz]

$var = "";



print $var;

?>

Works fine for me.

http://writecodeonline.com/php/

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