How to do try-except in python

[burn123]

I have this code

import random #bring in the random number
import time
number=random.randint(1, 200) #pick the number between 1 and 200

def intro():
print(“May I ask you for your name?”)
name=input() #asks for the name
print(name + “, we are going to play a game. I am thinking of a number between 1 and 200”)
time.sleep(.5)
print(“Go ahead. Guess!”)

def pick():
guessesTaken = 0
while guessesTaken < 6: #if the number of guesses is less than 6
time.sleep(.25)
enter=input(“Guess: “) #inserts the place to enter guess
try: #check if a number was entered
guess = int(enter) #stores the guess as an integer instead of a string

if guess<=200 and guess>=1: #if they are in range
guessesTaken=guessesTaken+1 #adds one guess each time the player is wrong
if guessesTaken<6:
if guess print(“The guess of the number that you have entered is too low”)
if guess>number:
print(“The guess of the number that you have entered is too high”)
if guess != number:
time.sleep(.5)
print(“Try Again!”)
if guess==number:
break #if the guess is right, then we are going to jump out of the while block
if guess>200 or guess<1: #if they aren't in the range
print(“Silly Goose! That number isn’t in the range!”)
time.sleep(.25)
print(“Please enter a number between 1 and 200”)

except: #if a number wasn’t entered
print(“I don’t think that “+enter+” is a number. Sorry”)

if guess == number:
guessesTaken = str(guessesTaken)
print(‘Good job, ‘ + name + ‘! You guessed my number in ‘ + guessesTaken + ‘ guesses!’)

if guess != number:
number = str(number)
print(‘Nope. The number I was thinking of was ‘ + number)

playagain=”yes”
while playagain==”yes” or playagain==”y” or playagain==”Yes”:
intro()
pick()
print(“Do you want to play again?”)
playagain=input()

I don’t know why, but if i run this script, no matter what I enter for my guess, it goes with

print(“I don’t think that “+enter+” is a number. Sorry”)

Even if it is a number. I am not sure how to fix this

[Author]

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