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Home Forums Back End Help adding a logout link to my footer menu!

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  • #203831

    Hi all

    I currently have this code in my functions.php to control my footer menu:

    `add_filter(‘omega_footer_insert’, ‘my_omega_footer_insert’, 11);

    function my_omega_footer_insert( $settings ) {
    $year = date( ‘Y’ );
    $siteurl = get_bloginfo( ‘url’ );
    $sitename = get_bloginfo( ‘name’ );
    return “<a href=’’>About</af=’’>Terms</a&gt; | <a href=’’>Privacy</a><br>© <a href=’$siteurl’>$sitename</a> $year</p>”;

    I want to add a logout link to this, which displays ONLY when a user is registered and logged in. I have this code:

    if ( is_user_logged_in() ) {
    echo ' | &lt;a href="&lt;?php echo wp_logout_url( get_permalink() ); ?&gt;" title="Logout"&gt;Logout&lt;/a&gt;';

    ..but I’m not having mu luck with it because I don’t know for certain that it’s correct, and secondly I’m not sure where it should be placed within the first bit of code above. Can anyone help please?

    Thank you!



    Please use something like to post your code if you’re not familiar with Markdown formatting.

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