Filtering Category Lists

[sBowers]

(Not sure if this questions belongs in wordpress or php)

I am filtering wordpress posts on a template using:

Code:

$cat,
‘showposts’ => $showposts,
‘caller_get_posts’ => $do_not_show_stickies
);
$my_query = new WP_Query($args);
?>

I need to filter

Code:

wp_list_categories()

list based on the page or category. ie On page "36" the list should only display categories "3" and the sub-categories under "3".

I think I am close. I used the same if statement in the sidebar file to set a variable $cat

Code:

$cat,
‘title_li’ =>”
);
?>

and then I call

Code:

But I am getting the following error:

Quote:

Warning: preg_split() expects parameter 2 to be string, array given in (path to) wp-includes/taxonomy.php on line 696

I can hard code the "include" into the

Code:

and it works fine.

Can you not pass a variable into this statement?

Any assistance is appreciated.

Seth

[Chris Coyier]

The "include" parameter wants a string, not an array. Just give it "3" instead of array(3). If you need multiple, just comma separate, like "3,4,5"

[sBowers]

So I was making it too complicated.

You have to call the hook during the if statement. ie

Code:

if (is_page(’36’) ) {
wp_list_categories(‘child_of=3&title_li=’);
} elseif ( is_page(’42’) ) {
wp_list_categories(‘child_of=4&title_li=’);
} elseif ( is_page(’44’) ) {
wp_list_categories(‘child_of=5&title_li=’);
} else {
wp_list_categories();
}

It will still need to be hard coded if the site changes but at least it works for now.

[sBowers]

"chriscoyier" wrote:

The "include" parameter wants a string, not an array. Just give it "3" instead of array(3). If you need multiple, just comma separate, like "3,4,5"

Thanks Chris. Love the screancasts. You have saved my bacon more then once.

[Author]

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