Show Specific Banners for Specific Pages

[Kralle]

Hello guys!

I am in a need of a little PHP script for a static website I’m making. I’m not using any CMS, just a few includes for the footer, header, menu etc.

On every single page there is a featured image/banner, and I’d like to use a little snippet in those specific pages to include the image based in the current page.

Here is how it’s outlined:
For instance, I have three images. When the ‘about.php’ is the current page, I want to display image number one, and when ‘contact.php’ is the current page, I want to display image number two. The third image is for the rest of all the pages. I was wondering if it’s possible to say something like (I have absolutely no PHP experience)

if ($currentpage == 'about.php') {

print("")

},

if ($currentpage == 'contact.php') {

print("")

},

else {

print("")

}

?>

I don’t know how to get the current page thingy. I’m using the following script to highlight the current menu item, and I was wondering if it’s possible to just customize that little bunch of code so it’ll work with the images.

function activestate($pagename, $currentpage) {

if ($pagename == $currentpage) {

echo "current";

}

}

?>





">Hello

Thanks in advance.

Best regards,
Kralle

[scheme]

basename($_SERVER)

… should do what you’re looking for. I’m not really sure if this is safe (regarding SQL injections), but as you are using a static web page it won’t be a problem.

[Kralle]

How would I implement

basename($_SERVER)

in the image-code – or even better, how would you write the final code? I really appreciate your help.

Thanks in advance,
Kralle

[Krist]

Dude.. Try this..

$currentpage = substr($_SERVER["SCRIPT_NAME"], strrpos($_SERVER["SCRIPT_NAME"],"/")+1);



if ($currentpage == 'page_1.php') {

echo '';

}

elseif ($currentpage == 'page_2.php') {

echo '';

}

elseif ($currentpage == 'page_3.php') {

echo '';

}

else {

echo '';

}

?>

[Kralle]

You, sir, are a legend. Thanks a bunch man. It works perfectly!

[Author]

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