- This topic is empty.
-
AuthorPosts
-
April 10, 2009 at 9:47 am #24552saifulMember
this is my pic.php
i want to load image into mysql database table how pls any one help me<?php
include_once(‘config.php’);//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","100");//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) – $i;
$ext = substr($str,$i+1,$l);
return $ext;
}//This variable is used as a flag. The value is initialized with 0 (meaning no error found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
$errors=0;
//checks if the form has been submitted
if(isset($_POST))
{
//reads the name of the file the user submitted for uploading
$image=$_FILES;
//if it is not empty
if ($image)
{
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
//if it is not a known extension, we will suppose it is an error and will not upload the file,
//otherwise we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
//print error message
echo ‘<h1>Unknown extension!</h1>’;
$errors=1;
}
else
{
//get the size of the image in bytes
//$_FILES is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES);//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo ‘<h1>You have exceeded the size limit!</h1>’;
$errors=1;
}//we will give an unique name, for example the time in unix time format
$image_name=time().’.’.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname="images/".$image_name;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES, $newname);
if (!$copied)
{
echo ‘<h1>Copy unsuccessfull!</h1>’;
$errors=1;
}}}}//If no errors registred, print the success message
if(isset($_POST) && !$errors)
{
echo "<h1>File Uploaded Successfully</h1>";
}?>
<!–next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" –>
<form name="newad" method="post" enctype="multipart/form-data" action="show.php">
<table>
<tr><td><input type="file" name="image"></td></tr>
<tr><td><input name="Submit" type="submit" value="Upload image"></td></tr>
</table>
</form>April 28, 2009 at 12:37 pm #56856akeenlabsParticipantI’m confused. The code you posted is correct and will successfully upload an image (I tried it myself).
Are you asking how to modify the sample code to put the file in a database instead of the images folder? If so, my response is you shouldn’t; you should never store an image in a database.
Are you asking how to store the path to the image in the database?
Please clarify.
-
AuthorPosts
- The forum ‘Back End’ is closed to new topics and replies.