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Home › Forums › JavaScript › Drop table rows on other table rows AND allow re-ordering? (jQuery UI sortable/draggable/droppable?)
I’m out of ideas.
I have a list of table rows that i need to sort. No problem, jQuery UI’s `sortable()` will do that for me. The thing is, i need to be able to drop the dragged element on top of other rows as well. If a row is dropped on top of another row the dragged row should disappear (i’d make som ajax stuff under the hood).
Take a look at this demo:
http://jqueryui.com/sortable/
That’s exactly what i want, except i also want to be able to drop the dragged element on other rows.
I don’t have to use jQuery UI if there are better alternatives, i just stuck with it because it already kind of does what i need.
This is pretty much what i’ve got:
http://jsfiddle.net/m79Sg/
I’ve played around with `draggable()` and `droppable()` but haven’t gotten the result i’m looking for.
Any suggestions?
**Update**
I made some progress. I managed to combine `sortable` with `droppable`, but i’m not quite done yet. It doesn’t work as i need it to.
Check this jsfiddle out: http://jsfiddle.net/bRbSn/30/
If you want to drop a row between two other rows, it still thinks you are dropping it ON another row, thus causing it to disappear. I still want to be able to re-order the rows by dropping them on the gap between. Tried playing around with the `tolerance` option, but it made no difference for me.