Date issue

[thisishard]

Ok, I have a variable which is a date, "2010.03.09" – yyyy.mm.dd
I want to subtract one day from it and echo out "2010.03.08" or what ever the value is from subtracting one from the date given.
Any help appreciated
Thanks

[Makeshift]

Give this a try:

Code:

$d = date(“d”)-1;
$date = date(“Y.m.”.$d);
echo $date;

[Makeshift]

Wait, if it’s a variable that’s already set, I would use this function:

Code:

function fix_date($var){
$var = explode(“.”, $var);
$day = $var[2];
$day = $day-1;
while(strlen($day)<2){
$day = '0'.$day;
}
$var = $var[0].'.'.$var[1];
$var .= '.'.$day;
echo $var;
}
fix_date('2010.03.09');

There’s probably easier ways to go about doing this, but this is what I would do.

[Makeshift]

Unfortunately it does not. But what you could do is set the timezone 24hrs backwards…

[Makeshift]

This function is a bit longer, but see if it works..

Code:

function fix_date($var){
$var = explode(“.”, $var);
$jan = “31”;
if(date(“L”) == 1){
$feb = 29;
}else{
$feb = 28;
}
$mar = 31;
$apr = 30;
$may = 31;
$jun = 30;
$jul = 31;
$aug = 31;
$sep = 30;
$oct = 31;
$nov = 30;
$dec = 31;

$year = $var[0];
$month = $var[1];
$day = $var[2];
$day = $day-1;
if($day < 1){ $month = $month-1; if($month > 1){
if($month == 1){
$day = $jan;
}elseif($month == 2){
$day = $feb;
}elseif($month == 3){
$day = $mar;
}elseif($month == 4){
$day = $apr;
}elseif($month == 5){
$day = $may;
}elseif($month == 6){
$day = $jun;
}elseif($month == 7){
$day = $jul;
}elseif($month == 8){
$day = $aug;
}elseif($month == 9){
$day = $sep;
}elseif($month == 10){
$day = $oct;
}elseif($month == 11){
$day = $nov;
}elseif($month == 12){
$day = $dec;
}
}else{
$month = 12;
$year = $year-1;
$day = $dec;
}
}
while(strlen($day)<2){
$day = '0'.$day;
}
while(strlen($month)<2){
$month = '0'.$month;
}
$var = $year . '.' . $month . '.' . $day;
echo $var;
}
fix_date('2010.03.09');

If the day is january 1st, 2010 it will output: 2009.12.31

[davesgonebananas]

"thisishard" wrote:

I tried to make this work,

Code:

$date = (“01.03.2010”);
$newdate = strtotime ( ‘+1 day’ , strtotime ( $date ) ) ;
$newdate = date ( ‘d-m-Y’ , $newdate );
echo $newdate;

But it fails miserably.
Any ideas?

Works like a charm for me, what’s your problem exactly?

[Author]

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