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ajnoguerra

Hi guys, can anyone please help me out: How do I get each value of an array and put it in separate variables.

here's the array:

Array ( [0] => 1946 [1] => 6 [2] => 10 )

This is a birthday in an array, I'd like to get each value and put it in 3 variables which is the $Year, $Month, $Day. So I can output it as "Month Day, Year".

Please please help. Thanks.

CrocoDillon

Your array declaration is invalid. If you make it like:

  array(1946, 6, 10);

or

  array(0 => 1946, 1 => 6, 2 => 10);

if you must, you can then use

  $year = $whatever_array[0];

ajnoguerra

Actually got an answer for this problem. :D

$selectbirthday = array ( [0] => 1946 [1] => 6 [2] => 10 );

$resultyear = $selectbirthday[0];

echo $resultyear;

output is: 1946

CrocoDillon

Really? What PHP version do you use because I definitely getting an error on that array syntax (PHP Version 5.3.13)

ajnoguerra

@CrocoDillon, what you posted recently was correct. I actually forgot to mention that I fetched the values of the array from a database field and used "explode()" function to reference them individually. This is actually the output when I print_r "array ( [0] => 1946 [1] => 6 [2] => 10 );"

But this is the correct way:

$selectbirthday = array( 0 => 1946, 1 => 6, 2 => 10 );

$resultyear = $selectbirthday[0];

echo $resultyear;

Thanks for the help! (thumbs up)

CrocoDillon

You sure know how to puzzle my mind! I'm glad it's solved :)

traq

you could also do like so:

  <?php
  $ymd = array( 1946,6,10 );
  list( $year,$month,$day ) = $ymd;
  print "Year: $year";

list() is underappreciated... : )

treehouse : what would you like to learn today?

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[Solved] How do I get each value of an array and put it in separate variables.